http://www.maquinasexpendedoras.net/info-general/a-vending-machine-automatically-pours-soft-drinks-into-cups-the-amount-of-soft-drink-dispensed-into-a-cup-is.php el negocio de las máquinas expendedoras. fácil y simple. Sat, 19 May 2012 08:48:42 +0000 http://wordpress.org/?v=2.6.1 http://www.maquinasexpendedoras.net/info-general/a-vending-machine-automatically-pours-soft-drinks-into-cups-the-amount-of-soft-drink-dispensed-into-a-cup-is.php#comment-2261 WP Robot Wordpress Autoposter Tue, 19 Jan 2010 04:38:46 +0000 http://www.maquinasexpendedoras.net/info-general/a-vending-machine-automatically-pours-soft-drinks-into-cups-the-amount-of-soft-drink-dispensed-into-a-cup-is.php#comment-2261 For mu=7.6, sd=0.4 a) P( x > 8) = P(z>1) = 0.1587 b) P(x<8) = 1 - P( x > 8) = 1 - 0.1587 =0.8413 c) Number overflowing = 850 x 0.1587 =134.86 =135 approx For mu=7.6, sd=0.4
a)
P( x > = P(z>1) = 0.1587
b) P(x<8) = 1 - P( x > = 1 - 0.1587 =0.8413
c) Number overflowing = 850 x 0.1587 =134.86 =135 approx

]]> http://www.maquinasexpendedoras.net/info-general/a-vending-machine-automatically-pours-soft-drinks-into-cups-the-amount-of-soft-drink-dispensed-into-a-cup-is.php#comment-2260 blackout roller blinds Tue, 19 Jan 2010 04:38:45 +0000 http://www.maquinasexpendedoras.net/info-general/a-vending-machine-automatically-pours-soft-drinks-into-cups-the-amount-of-soft-drink-dispensed-into-a-cup-is.php#comment-2260 Given: normal distribution sample u = mean = 7.6 oz s = standard deviation = 0.4 oz Solution: (a) P = ? for x > 8 oz Solving for z yields z = (x - u) / s = (8 - 7.6) / 0.4 = 1 From the z-tables P(1) = 0.8413 (answer to b) for x<= 8 oz, therefore x > 8 oz is P(x>8) = 1 - 0.8413 = 0.1587 (15.87%) (b) P = ? for x <= 8 oz As derived from the z-tables (as shown above) P = 0.8413 (or 84.13%) (c) For N = 850 cups determine n with x > 8 oz. n = N * P(x>8) = 850 (0.1587) = 134.9 = 135 cups Here's a helpful site for TI-83/85 users http://mathbits.com/MathBits/TISection/S… Given:
normal distribution sample
u = mean = 7.6 oz
s = standard deviation = 0.4 oz
Solution:
(a) P = ? for x > 8 oz
Solving for z yields
z = (x - u) / s = (8 - 7.6) / 0.4 = 1
From the z-tables P(1) = 0.8413 (answer to b) for x< = 8 oz, therefore x > 8 oz is
P(x>8) = 1 - 0.8413 = 0.1587 (15.87%)
(b) P = ? for x < = 8 oz
As derived from the z-tables (as shown above)
P = 0.8413 (or 84.13%)
(c) For N = 850 cups determine n with x > 8 oz.
n = N * P(x>8) = 850 (0.1587) = 134.9
= 135 cups
Here’s a helpful site for TI-83/85 users http://mathbits.com/MathBits/TISection/S…

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